Look, you can’t complain about this after giving us so many scenarios involving N locked chests and M unlabeled keys.

https://explainxkcd.com/3015/

  • BreadstickNinja@lemmy.world
    link
    fedilink
    English
    arrow-up
    3
    ·
    edit-2
    17 days ago

    You fail the saving throw. The curse takes hold of you, the Bane of Thorny Improbability, which damns its bearer to be eternally plagued by probability and combinatorics conundra in their adventures.

    You know that you possess an antidote to stave off the worst effects of the curse, but you have three unlabeled flasks at your belt, all of which have an equal probability of being the cure. You choose a flask at random, but as you seek to dislodge it, one of the other flasks falls to the earth and shatters. The liquid eats through the rock of the cavern, giving off acrid smoke, and you recognize that the fallen vial was a deadly poison, not the cure.

    Knowing that the second flask did not contain the cure, do you have a better chance of salvation by drinking the flask you originally chose, or switching to the remaining unfallen flask?

    • deltapi@lemmy.world
      link
      fedilink
      English
      arrow-up
      2
      ·
      10 days ago

      I agree with the Cuban Dance. I’d switch the choice.

      Aside, do you DM? I love how you’ve written the above.

      • BreadstickNinja@lemmy.world
        link
        fedilink
        English
        arrow-up
        2
        ·
        10 days ago

        I used to DM quite a bit, though I’ve been a player in my last two campaigns! But I also like watching things like D20 and I read a fair bit of fantasy as well.